Base | Representation |
---|---|
bin | 1100001001001010010011… |
… | …0110111000000111111011 |
3 | 1202021101121200022100220101 |
4 | 3002102210312320013323 |
5 | 3222222410144030201 |
6 | 44221334444140231 |
7 | 2545421134136224 |
oct | 302224466700773 |
9 | 52241550270811 |
10 | 13351524205051 |
11 | 428839338193a |
12 | 15b7746537677 |
13 | 75b074272406 |
14 | 34230809c24b |
15 | 182485416d01 |
hex | c24a4db81fb |
13351524205051 has 2 divisors, whose sum is σ = 13351524205052. Its totient is φ = 13351524205050.
The previous prime is 13351524205037. The next prime is 13351524205081. The reversal of 13351524205051 is 15050242515331.
13351524205051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13351524205051 - 231 = 13349376721403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13351524205051.
It is not a weakly prime, because it can be changed into another prime (13351524205021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675762102525 + 6675762102526.
It is an arithmetic number, because the mean of its divisors is an integer number (6675762102526).
Almost surely, 213351524205051 is an apocalyptic number.
13351524205051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351524205051 is an equidigital number, since it uses as much as digits as its factorization.
13351524205051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 13351524205051 in words is "thirteen trillion, three hundred fifty-one billion, five hundred twenty-four million, two hundred five thousand, fifty-one".
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