Search a number
-
+
13351524205037 is a prime number
BaseRepresentation
bin1100001001001010010011…
…0110111000000111101101
31202021101121200022100212212
43002102210312320013231
53222222410144030122
644221334444140205
72545421134136204
oct302224466700755
952241550270785
1013351524205037
114288393381927
1215b7746537665
1375b0742723c5
1434230809c23b
15182485416ce2
hexc24a4db81ed

13351524205037 has 2 divisors, whose sum is σ = 13351524205038. Its totient is φ = 13351524205036.

The previous prime is 13351524205031. The next prime is 13351524205051. The reversal of 13351524205037 is 73050242515331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12007812022441 + 1343712182596 = 3465229^2 + 1159186^2 .

It is a cyclic number.

It is not a de Polignac number, because 13351524205037 - 24 = 13351524205021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13351524204985 and 13351524205003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13351524205031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675762102518 + 6675762102519.

It is an arithmetic number, because the mean of its divisors is an integer number (6675762102519).

Almost surely, 213351524205037 is an apocalyptic number.

It is an amenable number.

13351524205037 is a deficient number, since it is larger than the sum of its proper divisors (1).

13351524205037 is an equidigital number, since it uses as much as digits as its factorization.

13351524205037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 13351524205037 in words is "thirteen trillion, three hundred fifty-one billion, five hundred twenty-four million, two hundred five thousand, thirty-seven".