13351530244145 has 4 divisors (see below), whose sum is σ = 16021836292980. Its totient is φ = 10681224195312.

The previous prime is 13351530244097. The next prime is 13351530244201. The reversal of 13351530244145 is 54144203515331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6719251991104 + 6632278253041 = 2592152^2 + 2575321^2 .

It is a cyclic number.

It is not a de Polignac number, because 13351530244145 - 2⁸ = 13351530243889 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335153024410 + ... + 1335153024419.

It is an arithmetic number, because the mean of its divisors is an integer number (4005459073245).

Almost surely, 2^{13351530244145} is an apocalyptic number.

It is an amenable number.

13351530244145 is a deficient number, since it is larger than the sum of its proper divisors (2670306048835).

13351530244145 is an equidigital number, since it uses as much as digits as its factorization.

13351530244145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2670306048834.

The product of its (nonzero) digits is 432000, while the sum is 41.

Adding to 13351530244145 its reverse (54144203515331), we get a palindrome (67495733759476).

The spelling of 13351530244145 in words is "thirteen trillion, three hundred fifty-one billion, five hundred thirty million, two hundred forty-four thousand, one hundred forty-five".