13351530343442 has 4 divisors (see below), whose sum is σ = 20027295515166. Its totient is φ = 6675765171720.

The previous prime is 13351530343439. The next prime is 13351530343447. The reversal of 13351530343442 is 24434303515331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11316031772761 + 2035498570681 = 3363931^2 + 1426709^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13351530343442.

It is not an unprimeable number, because it can be changed into a prime (13351530343447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3337882585859 + ... + 3337882585862.

Almost surely, 2^{13351530343442} is an apocalyptic number.

13351530343442 is a deficient number, since it is larger than the sum of its proper divisors (6675765171724).

13351530343442 is an equidigital number, since it uses as much as digits as its factorization.

13351530343442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6675765171723.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 13351530343442 its reverse (24434303515331), we get a palindrome (37785833858773).

The spelling of 13351530343442 in words is "thirteen trillion, three hundred fifty-one billion, five hundred thirty million, three hundred forty-three thousand, four hundred forty-two".