Base | Representation |
---|---|
bin | 1100001001001010010101… |
… | …0101100000000110110110 |
3 | 1202021101122020102020101002 |
4 | 3002102211111200012312 |
5 | 3222222414222430032 |
6 | 44221335332203302 |
7 | 2545421262313565 |
oct | 302224525400666 |
9 | 52241566366332 |
10 | 13351532233142 |
11 | 4288397965524 |
12 | 15b7749169532 |
13 | 75b075b2356c |
14 | 34230918bbdc |
15 | 182485ea0862 |
hex | c24a55601b6 |
13351532233142 has 4 divisors (see below), whose sum is σ = 20027298349716. Its totient is φ = 6675766116570.
The previous prime is 13351532233139. The next prime is 13351532233157. The reversal of 13351532233142 is 24133223515331.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13351532233096 and 13351532233105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3337883058284 + ... + 3337883058287.
It is an arithmetic number, because the mean of its divisors is an integer number (5006824587429).
Almost surely, 213351532233142 is an apocalyptic number.
13351532233142 is a deficient number, since it is larger than the sum of its proper divisors (6675766116574).
13351532233142 is an equidigital number, since it uses as much as digits as its factorization.
13351532233142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6675766116573.
The product of its digits is 194400, while the sum is 38.
Adding to 13351532233142 its reverse (24133223515331), we get a palindrome (37484755748473).
The spelling of 13351532233142 in words is "thirteen trillion, three hundred fifty-one billion, five hundred thirty-two million, two hundred thirty-three thousand, one hundred forty-two".
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