Base | Representation |
---|---|
bin | 1100001001001010010101… |
… | …0101111000110101101101 |
3 | 1202021101122020121101100001 |
4 | 3002102211111320311231 |
5 | 3222222414234200240 |
6 | 44221335334304301 |
7 | 2545421263215124 |
oct | 302224525706555 |
9 | 52241566541301 |
10 | 13351532334445 |
11 | 4288397a24648 |
12 | 15b77491b8091 |
13 | 75b075b5a6c6 |
14 | 3423091b6abb |
15 | 182485ec089a |
hex | c24a5578d6d |
13351532334445 has 16 divisors (see below), whose sum is σ = 16587234639360. Its totient is φ = 10304869470784.
The previous prime is 13351532334431. The next prime is 13351532334463. The reversal of 13351532334445 is 54443323515331.
13351532334445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13351532334445 - 27 = 13351532334317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13351532334395 and 13351532334404.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35698429 + ... + 36070498.
It is an arithmetic number, because the mean of its divisors is an integer number (1036702164960).
Almost surely, 213351532334445 is an apocalyptic number.
It is an amenable number.
13351532334445 is a deficient number, since it is larger than the sum of its proper divisors (3235702304915).
13351532334445 is a wasteful number, since it uses less digits than its factorization.
13351532334445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71770244.
The product of its digits is 3888000, while the sum is 46.
Adding to 13351532334445 its reverse (54443323515331), we get a palindrome (67794855849776).
The spelling of 13351532334445 in words is "thirteen trillion, three hundred fifty-one billion, five hundred thirty-two million, three hundred thirty-four thousand, four hundred forty-five".
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