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13351998481441 is a prime number
BaseRepresentation
bin1100001001001100000100…
…1000000110010000100001
31202021102211201202002210121
43002103001020012100201
53222224343102401231
644221453505400241
72545435653335224
oct302230110062041
952242751662717
1013351998481441
1142886070697a4
1215b7859339081
1375b11b5bbb29
143423510795bb
151824b1d9d311
hexc24c1206421

13351998481441 has 2 divisors, whose sum is σ = 13351998481442. Its totient is φ = 13351998481440.

The previous prime is 13351998481433. The next prime is 13351998481543. The reversal of 13351998481441 is 14418489915331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13331232230416 + 20766251025 = 3651196^2 + 144105^2 .

It is a cyclic number.

It is not a de Polignac number, because 13351998481441 - 23 = 13351998481433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13351998481441.

It is not a weakly prime, because it can be changed into another prime (13351998431441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675999240720 + 6675999240721.

It is an arithmetic number, because the mean of its divisors is an integer number (6675999240721).

Almost surely, 213351998481441 is an apocalyptic number.

It is an amenable number.

13351998481441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13351998481441 is an equidigital number, since it uses as much as digits as its factorization.

13351998481441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14929920, while the sum is 61.

The spelling of 13351998481441 in words is "thirteen trillion, three hundred fifty-one billion, nine hundred ninety-eight million, four hundred eighty-one thousand, four hundred forty-one".