13352002124040 has 384 divisors, whose sum is σ = 45533804659200. Its totient is φ = 3386732912640.

The previous prime is 13352002124039. The next prime is 13352002124051. The reversal of 13352002124040 is 4042120025331.

13352002124040 is a `hidden beast` number, since 1 + 3 + 35 + 200 + 21 + 2 + 404 + 0 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 13352002123995 and 13352002124013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1510573941 + ... + 1510582779.

It is an arithmetic number, because the mean of its divisors is an integer number (118577616300).

Almost surely, 2^{13352002124040} is an apocalyptic number.

13352002124040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13352002124040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22766902329600).

13352002124040 is an abundant number, since it is smaller than the sum of its proper divisors (32181802535160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13352002124040 is a wasteful number, since it uses less digits than its factorization.

13352002124040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9877 (or 9870 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 27.

Adding to 13352002124040 its reverse (4042120025331), we get a palindrome (17394122149371).

The spelling of 13352002124040 in words is "thirteen trillion, three hundred fifty-two billion, two million, one hundred twenty-four thousand, forty".