Base | Representation |
---|---|
bin | 1100001001001100000111… |
… | …1101100111010010000101 |
3 | 1202021102212201010211211111 |
4 | 3002103001331213102011 |
5 | 3222224410200312331 |
6 | 44221455130205021 |
7 | 2545436213514631 |
oct | 302230175472205 |
9 | 52242781124744 |
10 | 13352012510341 |
11 | 4288613a8092a |
12 | 15b7861b83771 |
13 | 75b12149145b |
14 | 342352c8bdc1 |
15 | 1824b321edb1 |
hex | c24c1f67485 |
13352012510341 has 2 divisors, whose sum is σ = 13352012510342. Its totient is φ = 13352012510340.
The previous prime is 13352012510321. The next prime is 13352012510383. The reversal of 13352012510341 is 14301521025331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7658109794241 + 5693902716100 = 2767329^2 + 2386190^2 .
It is a cyclic number.
It is not a de Polignac number, because 13352012510341 - 211 = 13352012508293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13352012510321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676006255170 + 6676006255171.
It is an arithmetic number, because the mean of its divisors is an integer number (6676006255171).
Almost surely, 213352012510341 is an apocalyptic number.
It is an amenable number.
13352012510341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13352012510341 is an equidigital number, since it uses as much as digits as its factorization.
13352012510341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13352012510341 its reverse (14301521025331), we get a palindrome (27653533535672).
The spelling of 13352012510341 in words is "thirteen trillion, three hundred fifty-two billion, twelve million, five hundred ten thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •