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13352012510341 is a prime number
BaseRepresentation
bin1100001001001100000111…
…1101100111010010000101
31202021102212201010211211111
43002103001331213102011
53222224410200312331
644221455130205021
72545436213514631
oct302230175472205
952242781124744
1013352012510341
114288613a8092a
1215b7861b83771
1375b12149145b
14342352c8bdc1
151824b321edb1
hexc24c1f67485

13352012510341 has 2 divisors, whose sum is σ = 13352012510342. Its totient is φ = 13352012510340.

The previous prime is 13352012510321. The next prime is 13352012510383. The reversal of 13352012510341 is 14301521025331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7658109794241 + 5693902716100 = 2767329^2 + 2386190^2 .

It is a cyclic number.

It is not a de Polignac number, because 13352012510341 - 211 = 13352012508293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13352012510321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676006255170 + 6676006255171.

It is an arithmetic number, because the mean of its divisors is an integer number (6676006255171).

Almost surely, 213352012510341 is an apocalyptic number.

It is an amenable number.

13352012510341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352012510341 is an equidigital number, since it uses as much as digits as its factorization.

13352012510341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13352012510341 its reverse (14301521025331), we get a palindrome (27653533535672).

The spelling of 13352012510341 in words is "thirteen trillion, three hundred fifty-two billion, twelve million, five hundred ten thousand, three hundred forty-one".