Base | Representation |
---|---|
bin | 10011011011100001111… |
… | …110100101000110000111 |
3 | 11201122110112221210221202 |
4 | 103123201332211012013 |
5 | 133334023132441411 |
6 | 2501221405133115 |
7 | 165316162300052 |
oct | 23334176450607 |
9 | 4648415853852 |
10 | 1335231140231 |
11 | 4752a519530a |
12 | 19693a25a19b |
13 | 98bb1189391 |
14 | 488a8661a99 |
15 | 24aebe1183b |
hex | 136e1fa5187 |
1335231140231 has 2 divisors, whose sum is σ = 1335231140232. Its totient is φ = 1335231140230.
The previous prime is 1335231140189. The next prime is 1335231140261. The reversal of 1335231140231 is 1320411325331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1335231140231 - 26 = 1335231140167 is a prime.
It is a super-2 number, since 2×13352311402312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1335231140194 and 1335231140203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1335231140261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667615570115 + 667615570116.
It is an arithmetic number, because the mean of its divisors is an integer number (667615570116).
Almost surely, 21335231140231 is an apocalyptic number.
1335231140231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1335231140231 is an equidigital number, since it uses as much as digits as its factorization.
1335231140231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 1335231140231 its reverse (1320411325331), we get a palindrome (2655642465562).
The spelling of 1335231140231 in words is "one trillion, three hundred thirty-five billion, two hundred thirty-one million, one hundred forty thousand, two hundred thirty-one".
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