Base | Representation |
---|---|
bin | 10011011011100001111… |
… | …110100101000110001011 |
3 | 11201122110112221210221220 |
4 | 103123201332211012023 |
5 | 133334023132441420 |
6 | 2501221405133123 |
7 | 165316162300056 |
oct | 23334176450613 |
9 | 4648415853856 |
10 | 1335231140235 |
11 | 4752a5195313 |
12 | 19693a25a1a3 |
13 | 98bb1189395 |
14 | 488a8661a9d |
15 | 24aebe11840 |
hex | 136e1fa518b |
1335231140235 has 16 divisors (see below), whose sum is σ = 2136407239680. Its totient is φ = 712110803040.
The previous prime is 1335231140231. The next prime is 1335231140261. The reversal of 1335231140235 is 5320411325331.
It is not a de Polignac number, because 1335231140235 - 22 = 1335231140231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1335231140196 and 1335231140205.
It is not an unprimeable number, because it can be changed into a prime (1335231140231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 140580 + ... + 1640190.
It is an arithmetic number, because the mean of its divisors is an integer number (133525452480).
Almost surely, 21335231140235 is an apocalyptic number.
1335231140235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1335231140235 is a deficient number, since it is larger than the sum of its proper divisors (801176099445).
1335231140235 is a wasteful number, since it uses less digits than its factorization.
1335231140235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1558978.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1335231140235 its reverse (5320411325331), we get a palindrome (6655642465566).
The spelling of 1335231140235 in words is "one trillion, three hundred thirty-five billion, two hundred thirty-one million, one hundred forty thousand, two hundred thirty-five".
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