Search a number
-
+
13352445250141 is a prime number
BaseRepresentation
bin1100001001001101101111…
…0000011000101001011101
31202021110222212102022020111
43002103123300120221131
53222231301441001031
644222010105250021
72545453016655664
oct302233360305135
952243885368214
1013352445250141
114288816278728
1215b7962a93911
1375b190026aca
14342394535ddb
151824db1ee1b1
hexc24dbc18a5d

13352445250141 has 2 divisors, whose sum is σ = 13352445250142. Its totient is φ = 13352445250140.

The previous prime is 13352445250129. The next prime is 13352445250163. The reversal of 13352445250141 is 14105254425331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13100888835225 + 251556414916 = 3619515^2 + 501554^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13352445250141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13352445250094 and 13352445250103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13352445250541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676222625070 + 6676222625071.

It is an arithmetic number, because the mean of its divisors is an integer number (6676222625071).

Almost surely, 213352445250141 is an apocalyptic number.

It is an amenable number.

13352445250141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352445250141 is an equidigital number, since it uses as much as digits as its factorization.

13352445250141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 13352445250141 its reverse (14105254425331), we get a palindrome (27457699675472).

The spelling of 13352445250141 in words is "thirteen trillion, three hundred fifty-two billion, four hundred forty-five million, two hundred fifty thousand, one hundred forty-one".