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13352445351997 is a prime number
BaseRepresentation
bin1100001001001101101111…
…0000110001100000111101
31202021110222212121110221221
43002103123300301200331
53222231302002230442
644222010111353341
72545453020561643
oct302233360614075
952243885543857
1013352445351997
114288816338204
1215b7962b22851
1375b19006128b
14342394561193
151824db21e467
hexc24dbc3183d

13352445351997 has 2 divisors, whose sum is σ = 13352445351998. Its totient is φ = 13352445351996.

The previous prime is 13352445351953. The next prime is 13352445352031. The reversal of 13352445351997 is 79915354425331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9508379276356 + 3844066075641 = 3083566^2 + 1960629^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13352445351997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13352445321997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676222675998 + 6676222675999.

It is an arithmetic number, because the mean of its divisors is an integer number (6676222675999).

Almost surely, 213352445351997 is an apocalyptic number.

It is an amenable number.

13352445351997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352445351997 is an equidigital number, since it uses as much as digits as its factorization.

13352445351997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 61236000, while the sum is 61.

The spelling of 13352445351997 in words is "thirteen trillion, three hundred fifty-two billion, four hundred forty-five million, three hundred fifty-one thousand, nine hundred ninety-seven".