Base | Representation |
---|---|
bin | 1100001001001101101111… |
… | …0000110001100001100111 |
3 | 1202021110222212121111000111 |
4 | 3002103123300301201213 |
5 | 3222231302002231124 |
6 | 44222010111353451 |
7 | 2545453020562033 |
oct | 302233360614147 |
9 | 52243885544014 |
10 | 13352445352039 |
11 | 4288816338242 |
12 | 15b7962b22887 |
13 | 75b1900612c1 |
14 | 3423945611c3 |
15 | 1824db21e494 |
hex | c24dbc31867 |
13352445352039 has 2 divisors, whose sum is σ = 13352445352040. Its totient is φ = 13352445352038.
The previous prime is 13352445352031. The next prime is 13352445352121. The reversal of 13352445352039 is 93025354425331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13352445352039 - 23 = 13352445352031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13352445351983 and 13352445352001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13352445352031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676222676019 + 6676222676020.
It is an arithmetic number, because the mean of its divisors is an integer number (6676222676020).
Almost surely, 213352445352039 is an apocalyptic number.
13352445352039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13352445352039 is an equidigital number, since it uses as much as digits as its factorization.
13352445352039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832000, while the sum is 49.
The spelling of 13352445352039 in words is "thirteen trillion, three hundred fifty-two billion, four hundred forty-five million, three hundred fifty-two thousand, thirty-nine".
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