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13352451205531 is a prime number
BaseRepresentation
bin1100001001001101110000…
…0111000110100110011011
31202021111000021121212111111
43002103130013012212123
53222231310002034111
644222010441041151
72545453121411434
oct302233407064633
952244007555444
1013352451205531
114288819676039
1215b7964a861b7
1375b1913306c9
1434239524648b
151824db9c8a21
hexc24dc1c699b

13352451205531 has 2 divisors, whose sum is σ = 13352451205532. Its totient is φ = 13352451205530.

The previous prime is 13352451205517. The next prime is 13352451205571. The reversal of 13352451205531 is 13550215425331.

It is an a-pointer prime, because the next prime (13352451205571) can be obtained adding 13352451205531 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13352451205531 - 221 = 13352449108379 is a prime.

It is a super-2 number, since 2×133524512055312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13352451205571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676225602765 + 6676225602766.

It is an arithmetic number, because the mean of its divisors is an integer number (6676225602766).

Almost surely, 213352451205531 is an apocalyptic number.

13352451205531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352451205531 is an equidigital number, since it uses as much as digits as its factorization.

13352451205531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270000, while the sum is 40.

The spelling of 13352451205531 in words is "thirteen trillion, three hundred fifty-two billion, four hundred fifty-one million, two hundred five thousand, five hundred thirty-one".