Base | Representation |
---|---|
bin | 1100001001001101111100… |
… | …0010110110111010001111 |
3 | 1202021111010201020110000011 |
4 | 3002103133002312322033 |
5 | 3222231410102034320 |
6 | 44222015400014051 |
7 | 2545454256643462 |
oct | 302233702667217 |
9 | 52244121213004 |
10 | 13352500424335 |
11 | 4288844432936 |
12 | 15b7979461327 |
13 | 75b19b5a4367 |
14 | 34239b9b92d9 |
15 | 1824e0e9c05a |
hex | c24df0b6e8f |
13352500424335 has 32 divisors (see below), whose sum is σ = 16735069670400. Its totient is φ = 10214850455040.
The previous prime is 13352500424299. The next prime is 13352500424381. The reversal of 13352500424335 is 53342400525331.
It is not a de Polignac number, because 13352500424335 - 241 = 11153477168783 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5289477 + ... + 7394833.
It is an arithmetic number, because the mean of its divisors is an integer number (522970927200).
Almost surely, 213352500424335 is an apocalyptic number.
13352500424335 is a deficient number, since it is larger than the sum of its proper divisors (3382569246065).
13352500424335 is a wasteful number, since it uses less digits than its factorization.
13352500424335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2105811.
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 13352500424335 its reverse (53342400525331), we get a palindrome (66694900949666).
The spelling of 13352500424335 in words is "thirteen trillion, three hundred fifty-two billion, five hundred million, four hundred twenty-four thousand, three hundred thirty-five".
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