Base | Representation |
---|---|
bin | 1100001001001110000001… |
… | …0110101101011010011011 |
3 | 1202021111012020121012112112 |
4 | 3002103200112231122123 |
5 | 3222231431213434111 |
6 | 44222021503102535 |
7 | 2545454644533551 |
oct | 302234026553233 |
9 | 52244166535475 |
10 | 13352522405531 |
11 | 4288855886711 |
12 | 15b79848a1a4b |
13 | 75b1a2ccc49a |
14 | 3423a089bbd1 |
15 | 1824e2d8ee8b |
hex | c24e05ad69b |
13352522405531 has 4 divisors (see below), whose sum is σ = 14137964899992. Its totient is φ = 12567079911072.
The previous prime is 13352522405501. The next prime is 13352522405533. The reversal of 13352522405531 is 13550422525331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13352522405531 is a prime.
It is a super-2 number, since 2×133525224055312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13352522405533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 392721247205 + ... + 392721247238.
It is an arithmetic number, because the mean of its divisors is an integer number (3534491224998).
Almost surely, 213352522405531 is an apocalyptic number.
13352522405531 is a deficient number, since it is larger than the sum of its proper divisors (785442494461).
13352522405531 is an equidigital number, since it uses as much as digits as its factorization.
13352522405531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 785442494460.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 13352522405531 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-two million, four hundred five thousand, five hundred thirty-one".
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