Base | Representation |
---|---|
bin | 1100001001001110001000… |
… | …0100010101001010110111 |
3 | 1202021111021020200011122211 |
4 | 3002103202010111022313 |
5 | 3222232011043021241 |
6 | 44222024411034251 |
7 | 2545455444020551 |
oct | 302234204251267 |
9 | 52244236604584 |
10 | 13352551142071 |
11 | 4288870023919 |
12 | 15b799243b987 |
13 | 75b1a8c5135b |
14 | 3423a461c4d1 |
15 | 1824e5669781 |
hex | c24e21152b7 |
13352551142071 has 2 divisors, whose sum is σ = 13352551142072. Its totient is φ = 13352551142070.
The previous prime is 13352551142033. The next prime is 13352551142143. The reversal of 13352551142071 is 17024115525331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13352551142071 - 237 = 13215112188599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13352551142171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676275571035 + 6676275571036.
It is an arithmetic number, because the mean of its divisors is an integer number (6676275571036).
Almost surely, 213352551142071 is an apocalyptic number.
13352551142071 is a deficient number, since it is larger than the sum of its proper divisors (1).
13352551142071 is an equidigital number, since it uses as much as digits as its factorization.
13352551142071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126000, while the sum is 40.
The spelling of 13352551142071 in words is "thirteen trillion, three hundred fifty-two billion, five hundred fifty-one million, one hundred forty-two thousand, seventy-one".
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