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13353000144041 = 29795828459251
BaseRepresentation
bin1100001001001111110011…
…0101001000110010101001
31202021112102112112211120102
43002103330311020302221
53222233421014102131
644222141130435145
72545502535332315
oct302237465106251
952245375484512
1013353000144041
114288a80518728
1215b7a98892ab5
1375b24ac8b9ac
143424080dab45
1518251ecac1cb
hexc24fcd48ca9

13353000144041 has 8 divisors (see below), whose sum is σ = 13988302204800. Its totient is φ = 12729355002000.

The previous prime is 13353000144023. The next prime is 13353000144059. The reversal of 13353000144041 is 14044100035331.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (13353000144023) and next prime (13353000144059).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13353000144041 is a prime.

It is a super-2 number, since 2×133530001440412 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (29).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13353000143995 and 13353000144013.

It is not an unprimeable number, because it can be changed into a prime (13353000144641) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2914227335 + ... + 2914231916.

It is an arithmetic number, because the mean of its divisors is an integer number (1748537775600).

Almost surely, 213353000144041 is an apocalyptic number.

It is an amenable number.

13353000144041 is a deficient number, since it is larger than the sum of its proper divisors (635302060759).

13353000144041 is an equidigital number, since it uses as much as digits as its factorization.

13353000144041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5828459359.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 13353000144041 its reverse (14044100035331), we get a palindrome (27397100179372).

The spelling of 13353000144041 in words is "thirteen trillion, three hundred fifty-three billion, one hundred forty-four thousand, forty-one".

Divisors: 1 29 79 2291 5828459251 169025318279 460448280829 13353000144041