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1335300044053 = 19372731885519
BaseRepresentation
bin10011011011100110000…
…101011011010100010101
311201122122100121111020011
4103123212011123110111
5133334143302402203
62501232310040221
7165320660046613
oct23334605332425
94648570544204
101335300044053
11475330077818
12196959349071
1398bc2532c81
14488b387a6b3
1524b02ec276d
hex136e615b515

1335300044053 has 8 divisors (see below), whose sum is σ = 1405617449600. Its totient is φ = 1264986484128.

The previous prime is 1335300044051. The next prime is 1335300044107. The reversal of 1335300044053 is 3504400035331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1335300044053 - 21 = 1335300044051 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1335300044051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 234573 + ... + 1650946.

It is an arithmetic number, because the mean of its divisors is an integer number (175702181200).

Almost surely, 21335300044053 is an apocalyptic number.

It is an amenable number.

1335300044053 is a deficient number, since it is larger than the sum of its proper divisors (70317405547).

1335300044053 is a wasteful number, since it uses less digits than its factorization.

1335300044053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1922811.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 1335300044053 its reverse (3504400035331), we get a palindrome (4839700079384).

The spelling of 1335300044053 in words is "one trillion, three hundred thirty-five billion, three hundred million, forty-four thousand, fifty-three".

Divisors: 1 19 37273 708187 1885519 35824861 70278949687 1335300044053