Base | Representation |
---|---|
bin | 1100001001001111110110… |
… | …0100011001101100001001 |
3 | 1202021112110101212022102201 |
4 | 3002103331210121230021 |
5 | 3222233432202042100 |
6 | 44222142252200201 |
7 | 2545503045544603 |
oct | 302237544315411 |
9 | 52245411768381 |
10 | 13353012534025 |
11 | 4288a8751048a |
12 | 15b7aa0a69061 |
13 | 75b250709348 |
14 | 342409a04173 |
15 | 182520e0836a |
hex | c24fd919b09 |
13353012534025 has 12 divisors (see below), whose sum is σ = 16560115084800. Its totient is φ = 10680874838480.
The previous prime is 13353012534019. The next prime is 13353012534031. The reversal of 13353012534025 is 52043521035331.
It is an interprime number because it is at equal distance from previous prime (13353012534019) and next prime (13353012534031).
It is a de Polignac number, because none of the positive numbers 2k-13353012534025 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 38202265 + ... + 38550214.
It is an arithmetic number, because the mean of its divisors is an integer number (1380009590400).
Almost surely, 213353012534025 is an apocalyptic number.
It is an amenable number.
13353012534025 is a deficient number, since it is larger than the sum of its proper divisors (3207102550775).
13353012534025 is an equidigital number, since it uses as much as digits as its factorization.
13353012534025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76759448 (or 76759443 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 13353012534025 its reverse (52043521035331), we get a palindrome (65396533569356).
The spelling of 13353012534025 in words is "thirteen trillion, three hundred fifty-three billion, twelve million, five hundred thirty-four thousand, twenty-five".
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