Base | Representation |
---|---|
bin | 1100001001010000010000… |
… | …0110011111000111100010 |
3 | 1202021112202001002111012122 |
4 | 3002110010012133013202 |
5 | 3222234143231214300 |
6 | 44222201205224242 |
7 | 2545505546244542 |
oct | 302240406370742 |
9 | 52245661074178 |
10 | 13353122132450 |
11 | 42890333683a1 |
12 | 15b7b11702082 |
13 | 75b26a330999 |
14 | 34241a3b3322 |
15 | 18252a856c85 |
hex | c250419f1e2 |
13353122132450 has 24 divisors (see below), whose sum is σ = 24962882348052. Its totient is φ = 5314135910720.
The previous prime is 13353122132437. The next prime is 13353122132461. The reversal of 13353122132450 is 5423122135331.
It can be written as a sum of positive squares in 6 ways, for example, as 9055639729081 + 4297482403369 = 3009259^2 + 2073037^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13353122132450.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 677813609 + ... + 677833308.
Almost surely, 213353122132450 is an apocalyptic number.
13353122132450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13353122132450 is a deficient number, since it is larger than the sum of its proper divisors (11609760215602).
13353122132450 is a wasteful number, since it uses less digits than its factorization.
13353122132450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1355647126 (or 1355647121 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 13353122132450 its reverse (5423122135331), we get a palindrome (18776244267781).
The spelling of 13353122132450 in words is "thirteen trillion, three hundred fifty-three billion, one hundred twenty-two million, one hundred thirty-two thousand, four hundred fifty".
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