Base | Representation |
---|---|
bin | 11110010111001000111100… |
… | …111011110001110101011001 |
3 | 122111210111021200210121101001 |
4 | 132113020330323301311121 |
5 | 120000240111204124332 |
6 | 1151555314425225001 |
7 | 40061223266365126 |
oct | 3627107473616531 |
9 | 574714250717331 |
10 | 133531555536217 |
11 | 39602461a37853 |
12 | 12b87387932161 |
13 | 5967c82963477 |
14 | 24d8d6716174d |
15 | 10686dedb40e7 |
hex | 79723cef1d59 |
133531555536217 has 2 divisors, whose sum is σ = 133531555536218. Its totient is φ = 133531555536216.
The previous prime is 133531555536101. The next prime is 133531555536251. The reversal of 133531555536217 is 712635555135331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72051983862336 + 61479571673881 = 8488344^2 + 7840891^2 .
It is a cyclic number.
It is not a de Polignac number, because 133531555536217 - 27 = 133531555536089 is a prime.
It is not a weakly prime, because it can be changed into another prime (133531555536017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66765777768108 + 66765777768109.
It is an arithmetic number, because the mean of its divisors is an integer number (66765777768109).
Almost surely, 2133531555536217 is an apocalyptic number.
It is an amenable number.
133531555536217 is a deficient number, since it is larger than the sum of its proper divisors (1).
133531555536217 is an equidigital number, since it uses as much as digits as its factorization.
133531555536217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21262500, while the sum is 55.
The spelling of 133531555536217 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, five hundred fifty-five million, five hundred thirty-six thousand, two hundred seventeen".
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