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133531555536101 is a prime number
BaseRepresentation
bin11110010111001000111100…
…111011110001110011100101
3122111210111021200210121012202
4132113020330323301303211
5120000240111204123401
61151555314425224245
740061223266364602
oct3627107473616345
9574714250717182
10133531555536101
1139602461a37758
1212b87387932085
135967c829633b8
1424d8d671616a9
1510686dedb406b
hex79723cef1ce5

133531555536101 has 2 divisors, whose sum is σ = 133531555536102. Its totient is φ = 133531555536100.

The previous prime is 133531555536089. The next prime is 133531555536217. The reversal of 133531555536101 is 101635555135331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123993347152900 + 9538208383201 = 11135230^2 + 3088399^2 .

It is a cyclic number.

It is not a de Polignac number, because 133531555536101 - 214 = 133531555519717 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133531555506101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66765777768050 + 66765777768051.

It is an arithmetic number, because the mean of its divisors is an integer number (66765777768051).

Almost surely, 2133531555536101 is an apocalyptic number.

It is an amenable number.

133531555536101 is a deficient number, since it is larger than the sum of its proper divisors (1).

133531555536101 is an equidigital number, since it uses as much as digits as its factorization.

133531555536101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1518750, while the sum is 47.

The spelling of 133531555536101 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, five hundred fifty-five million, five hundred thirty-six thousand, one hundred one".