Base | Representation |
---|---|
bin | 11110010111001001100110… |
… | …010101110101010011101100 |
3 | 122111210120002002222210220010 |
4 | 132113021212111311103230 |
5 | 120000243022024411134 |
6 | 1151555511403053220 |
7 | 40061246433245316 |
oct | 3627114625652354 |
9 | 574716062883803 |
10 | 133532250232044 |
11 | 39602789094034 |
12 | 12b87540511210 |
13 | 59680638664a1 |
14 | 24d8dd15187b6 |
15 | 1068730d89ce9 |
hex | 7972665754ec |
133532250232044 has 12 divisors (see below), whose sum is σ = 311575250541464. Its totient is φ = 44510750077344.
The previous prime is 133532250231949. The next prime is 133532250232049. The reversal of 133532250232044 is 440232052235331.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 133532250231993 and 133532250232011.
It is not an unprimeable number, because it can be changed into a prime (133532250232049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5563843759657 + ... + 5563843759680.
Almost surely, 2133532250232044 is an apocalyptic number.
It is an amenable number.
133532250232044 is an abundant number, since it is smaller than the sum of its proper divisors (178043000309420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133532250232044 is a wasteful number, since it uses less digits than its factorization.
133532250232044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11127687519344 (or 11127687519342 counting only the distinct ones).
The product of its (nonzero) digits is 518400, while the sum is 39.
The spelling of 133532250232044 in words is "one hundred thirty-three trillion, five hundred thirty-two billion, two hundred fifty million, two hundred thirty-two thousand, forty-four".
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