1335333000145 has 8 divisors (see below), whose sum is σ = 1645707697704. Its totient is φ = 1039394335104.

The previous prime is 1335333000143. The next prime is 1335333000179. The reversal of 1335333000145 is 5410003335331.

It can be written as a sum of positive squares in 4 ways, for example, as 528226611264 + 807106388881 = 726792^2 + 898391^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1335333000145 - 2¹ = 1335333000143 is a prime.

It is a super-2 number, since 2×1335333000145² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1335333000143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3609007924 + ... + 3609008293.

It is an arithmetic number, because the mean of its divisors is an integer number (205713462213).

Almost surely, 2^{1335333000145} is an apocalyptic number.

It is an amenable number.

1335333000145 is a deficient number, since it is larger than the sum of its proper divisors (310374697559).

1335333000145 is an equidigital number, since it uses as much as digits as its factorization.

1335333000145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7218016259.

The product of its (nonzero) digits is 24300, while the sum is 31.

Adding to 1335333000145 its reverse (5410003335331), we get a palindrome (6745336335476).

The spelling of 1335333000145 in words is "one trillion, three hundred thirty-five billion, three hundred thirty-three million, one hundred forty-five", and thus it is an aban number.