Base | Representation |
---|---|
bin | 10011011011101000101… |
… | …110010111110100001100 |
3 | 11201122202102221112221010 |
4 | 103123220232113310030 |
5 | 133334241122111134 |
6 | 2501240531205220 |
7 | 165322035354252 |
oct | 23335056276414 |
9 | 4648672845833 |
10 | 1335344332044 |
11 | 475353076a68 |
12 | 196970146810 |
13 | 98bcb76b498 |
14 | 488b96c85d2 |
15 | 24b06d1ece9 |
hex | 136e8b97d0c |
1335344332044 has 24 divisors (see below), whose sum is σ = 3116039553648. Its totient is φ = 445081047040.
The previous prime is 1335344332043. The next prime is 1335344332057. The reversal of 1335344332044 is 4402334435331.
It is a happy number.
It is a super-3 number, since 3×13353443320443 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1335344331993 and 1335344332011.
It is not an unprimeable number, because it can be changed into a prime (1335344332043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4051077 + ... + 4368284.
It is an arithmetic number, because the mean of its divisors is an integer number (129834981402).
Almost surely, 21335344332044 is an apocalyptic number.
It is an amenable number.
1335344332044 is an abundant number, since it is smaller than the sum of its proper divisors (1780695221604).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1335344332044 is a wasteful number, since it uses less digits than its factorization.
1335344332044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8432585 (or 8432583 counting only the distinct ones).
The product of its (nonzero) digits is 622080, while the sum is 39.
Adding to 1335344332044 its reverse (4402334435331), we get a palindrome (5737678767375).
The spelling of 1335344332044 in words is "one trillion, three hundred thirty-five billion, three hundred forty-four million, three hundred thirty-two thousand, forty-four".
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