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13353472381 is a prime number
BaseRepresentation
bin11000110111110110…
…11101000101111101
31021110121220200102011
430123323131011331
5204321442104011
610045015131221
7651624433234
oct143373350575
937417820364
1013353472381
115732761497
122708073b11
13134a6a2562
1490969bb1b
155324c4621
hex31bedd17d

13353472381 has 2 divisors, whose sum is σ = 13353472382. Its totient is φ = 13353472380.

The previous prime is 13353472369. The next prime is 13353472387. The reversal of 13353472381 is 18327435331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11425472100 + 1928000281 = 106890^2 + 43909^2 .

It is an emirp because it is prime and its reverse (18327435331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13353472381 - 29 = 13353471869 is a prime.

It is a super-2 number, since 2×133534723812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353472387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676736190 + 6676736191.

It is an arithmetic number, because the mean of its divisors is an integer number (6676736191).

Almost surely, 213353472381 is an apocalyptic number.

It is an amenable number.

13353472381 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353472381 is an equidigital number, since it uses as much as digits as its factorization.

13353472381 is an evil number, because the sum of its binary digits is even.

The product of its digits is 181440, while the sum is 40.

The spelling of 13353472381 in words is "thirteen billion, three hundred fifty-three million, four hundred seventy-two thousand, three hundred eighty-one".