Base | Representation |
---|---|
bin | 1100001001010001110111… |
… | …0110110100000000101101 |
3 | 1202021120212011011101110021 |
4 | 3002110131312310000231 |
5 | 3222241034340400331 |
6 | 44222312122442141 |
7 | 2545522344106222 |
oct | 302243566640055 |
9 | 52246764141407 |
10 | 13353554231341 |
11 | 4289235267715 |
12 | 15b8012363351 |
13 | 75b308a006bc |
14 | 34245b931949 |
15 | 18255375b211 |
hex | c251ddb402d |
13353554231341 has 2 divisors, whose sum is σ = 13353554231342. Its totient is φ = 13353554231340.
The previous prime is 13353554231263. The next prime is 13353554231359. The reversal of 13353554231341 is 14313245535331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11621621902500 + 1731932328841 = 3409050^2 + 1316029^2 .
It is a cyclic number.
It is not a de Polignac number, because 13353554231341 - 227 = 13353420013613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13353554231141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676777115670 + 6676777115671.
It is an arithmetic number, because the mean of its divisors is an integer number (6676777115671).
Almost surely, 213353554231341 is an apocalyptic number.
It is an amenable number.
13353554231341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13353554231341 is an equidigital number, since it uses as much as digits as its factorization.
13353554231341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 972000, while the sum is 43.
Adding to 13353554231341 its reverse (14313245535331), we get a palindrome (27666799766672).
The spelling of 13353554231341 in words is "thirteen trillion, three hundred fifty-three billion, five hundred fifty-four million, two hundred thirty-one thousand, three hundred forty-one".
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