Base | Representation |
---|---|
bin | 1100001001010001110111… |
… | …0110110100110001010010 |
3 | 1202021120212011011112201102 |
4 | 3002110131312310301102 |
5 | 3222241034341000300 |
6 | 44222312122504402 |
7 | 2545522344121253 |
oct | 302243566646122 |
9 | 52246764145642 |
10 | 13353554234450 |
11 | 4289235269a91 |
12 | 15b8012365102 |
13 | 75b308a01c41 |
14 | 34245b932b2a |
15 | 18255375c0d5 |
hex | c251ddb4c52 |
13353554234450 has 24 divisors (see below), whose sum is σ = 24908778848100. Its totient is φ = 5326116753600.
The previous prime is 13353554234411. The next prime is 13353554234467. The reversal of 13353554234450 is 5443245535331.
It can be written as a sum of positive squares in 6 ways, for example, as 7279414445521 + 6074139788929 = 2698039^2 + 2464577^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13353554234395 and 13353554234404.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 382605881 + ... + 382640780.
Almost surely, 213353554234450 is an apocalyptic number.
13353554234450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13353554234450 is a deficient number, since it is larger than the sum of its proper divisors (11555224613650).
13353554234450 is a wasteful number, since it uses less digits than its factorization.
13353554234450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 765247022 (or 765247017 counting only the distinct ones).
The product of its (nonzero) digits is 6480000, while the sum is 47.
Adding to 13353554234450 its reverse (5443245535331), we get a palindrome (18796799769781).
The spelling of 13353554234450 in words is "thirteen trillion, three hundred fifty-three billion, five hundred fifty-four million, two hundred thirty-four thousand, four hundred fifty".
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