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13353554252959 is a prime number
BaseRepresentation
bin1100001001010001110111…
…0110111001010010011111
31202021120212011012111002221
43002110131312321102133
53222241034342043314
644222312123130211
72545522344226234
oct302243566712237
952246764174087
1013353554252959
114289235281988
1215b8012373967
1375b308a0a4ab
1434245b93978b
15182553762824
hexc251ddb949f

13353554252959 has 2 divisors, whose sum is σ = 13353554252960. Its totient is φ = 13353554252958.

The previous prime is 13353554252953. The next prime is 13353554253041. The reversal of 13353554252959 is 95925245535331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13353554252959 is a prime.

It is a super-2 number, since 2×133535542529592 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13353554252897 and 13353554252906.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353554252953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676777126479 + 6676777126480.

It is an arithmetic number, because the mean of its divisors is an integer number (6676777126480).

Almost surely, 213353554252959 is an apocalyptic number.

13353554252959 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353554252959 is an equidigital number, since it uses as much as digits as its factorization.

13353554252959 is an evil number, because the sum of its binary digits is even.

The product of its digits is 109350000, while the sum is 61.

The spelling of 13353554252959 in words is "thirteen trillion, three hundred fifty-three billion, five hundred fifty-four million, two hundred fifty-two thousand, nine hundred fifty-nine".