Base | Representation |
---|---|
bin | 11000110111111000… |
… | …01100000100000101 |
3 | 1021110122021110022210 |
4 | 30123330030010011 |
5 | 204322014233043 |
6 | 10045023214033 |
7 | 651626164161 |
oct | 143374140405 |
9 | 37418243283 |
10 | 13353664773 |
11 | 5732882a99 |
12 | 2708147319 |
13 | 134a73bcb7 |
14 | 90970bca1 |
15 | 532511633 |
hex | 31bf0c105 |
13353664773 has 4 divisors (see below), whose sum is σ = 17804886368. Its totient is φ = 8902443180.
The previous prime is 13353664763. The next prime is 13353664837. The reversal of 13353664773 is 37746635331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 37746635331 = 3 ⋅12582211777.
It is not a de Polignac number, because 13353664773 - 214 = 13353648389 is a prime.
It is a super-2 number, since 2×133536647732 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13353664703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2225610793 + ... + 2225610798.
It is an arithmetic number, because the mean of its divisors is an integer number (4451221592).
Almost surely, 213353664773 is an apocalyptic number.
It is an amenable number.
13353664773 is a deficient number, since it is larger than the sum of its proper divisors (4451221595).
13353664773 is an equidigital number, since it uses as much as digits as its factorization.
13353664773 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4451221594.
The product of its digits is 2857680, while the sum is 48.
The spelling of 13353664773 in words is "thirteen billion, three hundred fifty-three million, six hundred sixty-four thousand, seven hundred seventy-three".
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