13354002422041 has 4 divisors (see below), whose sum is σ = 14056844654800. Its totient is φ = 12651160189284.

The previous prime is 13354002422017. The next prime is 13354002422051. The reversal of 13354002422041 is 14022420045331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13354002422041 - 2⁵ = 13354002422009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13354002421994 and 13354002422012.

It is not an unprimeable number, because it can be changed into a prime (13354002422051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351421116351 + ... + 351421116388.

It is an arithmetic number, because the mean of its divisors is an integer number (3514211163700).

Almost surely, 2^{13354002422041} is an apocalyptic number.

It is an amenable number.

13354002422041 is a deficient number, since it is larger than the sum of its proper divisors (702842232759).

13354002422041 is an equidigital number, since it uses as much as digits as its factorization.

13354002422041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 702842232758.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 13354002422041 its reverse (14022420045331), we get a palindrome (27376422467372).

The spelling of 13354002422041 in words is "thirteen trillion, three hundred fifty-four billion, two million, four hundred twenty-two thousand, forty-one".