13354002530203 has 4 divisors (see below), whose sum is σ = 13934611335888. Its totient is φ = 12773393724520.

The previous prime is 13354002530173. The next prime is 13354002530261. The reversal of 13354002530203 is 30203520045331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13354002530203 - 2¹³ = 13354002522011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13354002530263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290304402808 + ... + 290304402853.

It is an arithmetic number, because the mean of its divisors is an integer number (3483652833972).

Almost surely, 2^{13354002530203} is an apocalyptic number.

13354002530203 is a deficient number, since it is larger than the sum of its proper divisors (580608805685).

13354002530203 is an equidigital number, since it uses as much as digits as its factorization.

13354002530203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 580608805684.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 13354002530203 its reverse (30203520045331), we get a palindrome (43557522575534).

The spelling of 13354002530203 in words is "thirteen trillion, three hundred fifty-four billion, two million, five hundred thirty thousand, two hundred three".