Base | Representation |
---|---|
bin | 1100001001010011101011… |
… | …1101000111011101101001 |
3 | 1202021122010011210002201012 |
4 | 3002110322331013131221 |
5 | 3222243034330020040 |
6 | 44222432402233305 |
7 | 2545540422503024 |
oct | 302247275073551 |
9 | 52248104702635 |
10 | 13354042423145 |
11 | 4289465899416 |
12 | 15b8129955835 |
13 | 75b385bacba8 |
14 | 3424a66d21bb |
15 | 182581540865 |
hex | c253af47769 |
13354042423145 has 4 divisors (see below), whose sum is σ = 16024850907780. Its totient is φ = 10683233938512.
The previous prime is 13354042423069. The next prime is 13354042423153. The reversal of 13354042423145 is 54132424045331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1481524718041 + 11872517705104 = 1217179^2 + 3445652^2 .
It is a cyclic number.
It is not a de Polignac number, because 13354042423145 - 212 = 13354042419049 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335404242310 + ... + 1335404242319.
It is an arithmetic number, because the mean of its divisors is an integer number (4006212726945).
Almost surely, 213354042423145 is an apocalyptic number.
It is an amenable number.
13354042423145 is a deficient number, since it is larger than the sum of its proper divisors (2670808484635).
13354042423145 is an equidigital number, since it uses as much as digits as its factorization.
13354042423145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2670808484634.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 13354042423145 its reverse (54132424045331), we get a palindrome (67486466468476).
The spelling of 13354042423145 in words is "thirteen trillion, three hundred fifty-four billion, forty-two million, four hundred twenty-three thousand, one hundred forty-five".
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