Base | Representation |
---|---|
bin | 11000110111111011… |
… | …01010011001001001 |
3 | 1021110200000002022212 |
4 | 30123331222121021 |
5 | 204322114114040 |
6 | 10045035354505 |
7 | 651632363501 |
oct | 143375523111 |
9 | 37420002285 |
10 | 13354051145 |
11 | 5733017306 |
12 | 27082b2a35 |
13 | 134a845b16 |
14 | 9097aca01 |
15 | 53258ad65 |
hex | 31bf6a649 |
13354051145 has 4 divisors (see below), whose sum is σ = 16024861380. Its totient is φ = 10683240912.
The previous prime is 13354051129. The next prime is 13354051163. The reversal of 13354051145 is 54115045331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3544535296 + 9809515849 = 59536^2 + 99043^2 .
It is a cyclic number.
It is not a de Polignac number, because 13354051145 - 24 = 13354051129 is a prime.
It is a super-2 number, since 2×133540511452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335405110 + ... + 1335405119.
It is an arithmetic number, because the mean of its divisors is an integer number (4006215345).
Almost surely, 213354051145 is an apocalyptic number.
It is an amenable number.
13354051145 is a deficient number, since it is larger than the sum of its proper divisors (2670810235).
13354051145 is an equidigital number, since it uses as much as digits as its factorization.
13354051145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2670810234.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 13354051145 its reverse (54115045331), we get a palindrome (67469096476).
The spelling of 13354051145 in words is "thirteen billion, three hundred fifty-four million, fifty-one thousand, one hundred forty-five".
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