Base | Representation |
---|---|
bin | 1100001001010011111010… |
… | …1101011010001101101111 |
3 | 1202021122021120022101121202 |
4 | 3002110332231122031233 |
5 | 3222243201441231021 |
6 | 44222442532320115 |
7 | 2545542116066231 |
oct | 302247655321557 |
9 | 52248246271552 |
10 | 13354105414511 |
11 | 42894984027a4 |
12 | 15b8146a7303b |
13 | 75b395c665a4 |
14 | 3424b0c0c251 |
15 | 182586d34a0b |
hex | c253eb5a36f |
13354105414511 has 4 divisors (see below), whose sum is σ = 13361775781224. Its totient is φ = 13346435047800.
The previous prime is 13354105414501. The next prime is 13354105414549. The reversal of 13354105414511 is 11541450145331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13354105414511 - 210 = 13354105413487 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13354105414501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3835180745 + ... + 3835184226.
It is an arithmetic number, because the mean of its divisors is an integer number (3340443945306).
Almost surely, 213354105414511 is an apocalyptic number.
13354105414511 is a deficient number, since it is larger than the sum of its proper divisors (7670366713).
13354105414511 is an equidigital number, since it uses as much as digits as its factorization.
13354105414511 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7670366712.
The product of its (nonzero) digits is 72000, while the sum is 38.
Adding to 13354105414511 its reverse (11541450145331), we get a palindrome (24895555559842).
The spelling of 13354105414511 in words is "thirteen trillion, three hundred fifty-four billion, one hundred five million, four hundred fourteen thousand, five hundred eleven".
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