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13354444015453 = 53251970641801
BaseRepresentation
bin1100001001010101001011…
…1001000100011101011101
31202021200011011110002210101
43002111102321010131131
53222244400131443303
644222540305541101
72545553400126052
oct302252271043535
952250134402711
1013354444015453
114289651551692
1215b8220344791
1375b41b15b188
14342503b8d029
151825a691ad1d
hexc2552e4475d

13354444015453 has 4 divisors (see below), whose sum is σ = 13606414657308. Its totient is φ = 13102473373600.

The previous prime is 13354444015439. The next prime is 13354444015477. The reversal of 13354444015453 is 35451044445331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10993912909849 + 2360531105604 = 3315707^2 + 1536402^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13354444015453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13354444016453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125985320848 + ... + 125985320953.

It is an arithmetic number, because the mean of its divisors is an integer number (3401603664327).

Almost surely, 213354444015453 is an apocalyptic number.

It is an amenable number.

13354444015453 is a deficient number, since it is larger than the sum of its proper divisors (251970641855).

13354444015453 is an equidigital number, since it uses as much as digits as its factorization.

13354444015453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 251970641854.

The product of its (nonzero) digits is 3456000, while the sum is 46.

The spelling of 13354444015453 in words is "thirteen trillion, three hundred fifty-four billion, four hundred forty-four million, fifteen thousand, four hundred fifty-three".

Divisors: 1 53 251970641801 13354444015453