Base | Representation |
---|---|
bin | 1100001001010101001011… |
… | …1010100100110010110011 |
3 | 1202021200011012012011001112 |
4 | 3002111102322210302303 |
5 | 3222244400232110120 |
6 | 44222540322223535 |
7 | 2545553403361331 |
oct | 302252272446263 |
9 | 52250135164045 |
10 | 13354444410035 |
11 | 42896517a1093 |
12 | 15b82204b4bab |
13 | 75b41b268961 |
14 | 342503c52b51 |
15 | 1825a6997bc5 |
hex | c2552ea4cb3 |
13354444410035 has 8 divisors (see below), whose sum is σ = 16868771886480. Its totient is φ = 10121263131744.
The previous prime is 13354444410031. The next prime is 13354444410053. The reversal of 13354444410035 is 53001444445331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13354444410035 - 22 = 13354444410031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13354444409974 and 13354444410001.
It is not an unprimeable number, because it can be changed into a prime (13354444410031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70286549432 + ... + 70286549621.
It is an arithmetic number, because the mean of its divisors is an integer number (2108596485810).
Almost surely, 213354444410035 is an apocalyptic number.
13354444410035 is a deficient number, since it is larger than the sum of its proper divisors (3514327476445).
13354444410035 is a wasteful number, since it uses less digits than its factorization.
13354444410035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 140573099077.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 13354444410035 its reverse (53001444445331), we get a palindrome (66355888855366).
The spelling of 13354444410035 in words is "thirteen trillion, three hundred fifty-four billion, four hundred forty-four million, four hundred ten thousand, thirty-five".
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