Base | Representation |
---|---|
bin | 1100001001010101001101… |
… | …0000110100111011111011 |
3 | 1202021200011121011111211020 |
4 | 3002111103100310323323 |
5 | 3222244403230241243 |
6 | 44222541051233523 |
7 | 2545553504065110 |
oct | 302252320647373 |
9 | 52250147144736 |
10 | 13354450243323 |
11 | 4289655015792 |
12 | 15b82224488a3 |
13 | 75b41c52bac7 |
14 | 342504930907 |
15 | 1825a724b283 |
hex | c2553434efb |
13354450243323 has 8 divisors (see below), whose sum is σ = 20349638466048. Its totient is φ = 7631114424744.
The previous prime is 13354450243319. The next prime is 13354450243331. The reversal of 13354450243323 is 32334205445331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13354450243323 - 22 = 13354450243319 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13354450243363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 317963101011 + ... + 317963101052.
It is an arithmetic number, because the mean of its divisors is an integer number (2543704808256).
Almost surely, 213354450243323 is an apocalyptic number.
13354450243323 is a deficient number, since it is larger than the sum of its proper divisors (6995188222725).
13354450243323 is an equidigital number, since it uses as much as digits as its factorization.
13354450243323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 635926202073.
The product of its (nonzero) digits is 1555200, while the sum is 42.
Adding to 13354450243323 its reverse (32334205445331), we get a palindrome (45688655688654).
The spelling of 13354450243323 in words is "thirteen trillion, three hundred fifty-four billion, four hundred fifty million, two hundred forty-three thousand, three hundred twenty-three".
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