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13354501541 = 71188091571
BaseRepresentation
bin11000110111111110…
…11000010110100101
31021110200211222011012
430123333120112211
5204322223022131
610045053152005
7651636250553
oct143377302645
937420758135
1013354501541
1157332a4737
12270848b605
13134a972b24
14909888bd3
1553262952b
hex31bfd85a5

13354501541 has 4 divisors (see below), whose sum is σ = 13542593184. Its totient is φ = 13166409900.

The previous prime is 13354501513. The next prime is 13354501549. The reversal of 13354501541 is 14510545331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13354501541 - 210 = 13354500517 is a prime.

It is a super-2 number, since 2×133545015412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13354501498 and 13354501507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13354501549) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94045715 + ... + 94045856.

It is an arithmetic number, because the mean of its divisors is an integer number (3385648296).

Almost surely, 213354501541 is an apocalyptic number.

It is an amenable number.

13354501541 is a deficient number, since it is larger than the sum of its proper divisors (188091643).

13354501541 is an equidigital number, since it uses as much as digits as its factorization.

13354501541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188091642.

The product of its (nonzero) digits is 18000, while the sum is 32.

The spelling of 13354501541 in words is "thirteen billion, three hundred fifty-four million, five hundred one thousand, five hundred forty-one".

Divisors: 1 71 188091571 13354501541