Base | Representation |
---|---|
bin | 111110001011111101… |
… | …0001000011110001101 |
3 | 110202200222200001020011 |
4 | 1330113322020132031 |
5 | 4142000021214242 |
6 | 141203314553221 |
7 | 12435241426234 |
oct | 1742772103615 |
9 | 422628601204 |
10 | 133545101197 |
11 | 516aa801132 |
12 | 21a6bb98811 |
13 | c7934a2851 |
14 | 666c247b1b |
15 | 37191cdd17 |
hex | 1f17e8878d |
133545101197 has 2 divisors, whose sum is σ = 133545101198. Its totient is φ = 133545101196.
The previous prime is 133545101191. The next prime is 133545101233. The reversal of 133545101197 is 791101545331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127742622921 + 5802478276 = 357411^2 + 76174^2 .
It is a cyclic number.
It is not a de Polignac number, because 133545101197 - 23 = 133545101189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133545101191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66772550598 + 66772550599.
It is an arithmetic number, because the mean of its divisors is an integer number (66772550599).
Almost surely, 2133545101197 is an apocalyptic number.
It is an amenable number.
133545101197 is a deficient number, since it is larger than the sum of its proper divisors (1).
133545101197 is an equidigital number, since it uses as much as digits as its factorization.
133545101197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56700, while the sum is 40.
The spelling of 133545101197 in words is "one hundred thirty-three billion, five hundred forty-five million, one hundred one thousand, one hundred ninety-seven".
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