Search a number
-
+
133554428437 = 1151116033387
BaseRepresentation
bin111110001100001110…
…1101101101000010101
3110202201122012220210111
41330120131231220111
54142004413202222
6141204250523021
712435413624323
oct1743035555025
9422648186714
10133554428437
1151704aa18a1
1221a73136471
13c7953ba121
14666d594d13
153719e22777
hex1f1876da15

133554428437 has 4 divisors (see below), whose sum is σ = 133670462976. Its totient is φ = 133438393900.

The previous prime is 133554428389. The next prime is 133554428443. The reversal of 133554428437 is 734824455331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 734824455331 = 4117922547691.

It is a cyclic number.

It is not a de Polignac number, because 133554428437 - 215 = 133554395669 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133554428477) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58015543 + ... + 58017844.

It is an arithmetic number, because the mean of its divisors is an integer number (33417615744).

Almost surely, 2133554428437 is an apocalyptic number.

It is an amenable number.

133554428437 is a deficient number, since it is larger than the sum of its proper divisors (116034539).

133554428437 is a wasteful number, since it uses less digits than its factorization.

133554428437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116034538.

The product of its digits is 4838400, while the sum is 49.

The spelling of 133554428437 in words is "one hundred thirty-three billion, five hundred fifty-four million, four hundred twenty-eight thousand, four hundred thirty-seven".

Divisors: 1 1151 116033387 133554428437