Base | Representation |
---|---|
bin | 10011011011111001010… |
… | …011000111110001101101 |
3 | 11201200110211011221000021 |
4 | 103123321103013301231 |
5 | 133340323313314013 |
6 | 2501324303202141 |
7 | 165331653043306 |
oct | 23337123076155 |
9 | 4650424157007 |
10 | 1335622401133 |
11 | 475486031429 |
12 | 196a292a6351 |
13 | 98c4425acc7 |
14 | 489045cd7ad |
15 | 24b2144aa8d |
hex | 136f94c7c6d |
1335622401133 has 2 divisors, whose sum is σ = 1335622401134. Its totient is φ = 1335622401132.
The previous prime is 1335622401079. The next prime is 1335622401161. The reversal of 1335622401133 is 3311042265331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 899153408169 + 436468992964 = 948237^2 + 660658^2 .
It is a cyclic number.
It is not a de Polignac number, because 1335622401133 - 233 = 1327032466541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1335622401233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667811200566 + 667811200567.
It is an arithmetic number, because the mean of its divisors is an integer number (667811200567).
Almost surely, 21335622401133 is an apocalyptic number.
It is an amenable number.
1335622401133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1335622401133 is an equidigital number, since it uses as much as digits as its factorization.
1335622401133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 1335622401133 its reverse (3311042265331), we get a palindrome (4646664666464).
The spelling of 1335622401133 in words is "one trillion, three hundred thirty-five billion, six hundred twenty-two million, four hundred one thousand, one hundred thirty-three".
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