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1336064734752 = 2531123713812251
BaseRepresentation
bin10011011100010011101…
…010011111011000100000
311201201121122111210122220
4103130103222133120200
5133342230033003002
62501440224031040
7165345633602556
oct23342352373040
94651548453586
101336064734752
11475692791200
12196b31462480
1398cb4aa2387
1448947253bd6
1524b4a1c27bc
hex13713a9f620

1336064734752 has 288 divisors, whose sum is σ = 3963804328512. Its totient is φ = 393465600000.

The previous prime is 1336064734673. The next prime is 1336064734843. The reversal of 1336064734752 is 2574374606331.

It is a junction number, because it is equal to n+sod(n) for n = 1336064734695 and 1336064734704.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 593541627 + ... + 593543877.

It is an arithmetic number, because the mean of its divisors is an integer number (13763209474).

Almost surely, 21336064734752 is an apocalyptic number.

1336064734752 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1336064734752, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1981902164256).

1336064734752 is an abundant number, since it is smaller than the sum of its proper divisors (2627739593760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1336064734752 is a wasteful number, since it uses less digits than its factorization.

1336064734752 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3704 (or 3685 counting only the distinct ones).

The product of its (nonzero) digits is 7620480, while the sum is 51.

The spelling of 1336064734752 in words is "one trillion, three hundred thirty-six billion, sixty-four million, seven hundred thirty-four thousand, seven hundred fifty-two".