Base | Representation |
---|---|
bin | 11110011000100110111001… |
… | …101110010101100000010010 |
3 | 122112011010200001022122221212 |
4 | 132120212321232111200102 |
5 | 120003413210423141424 |
6 | 1152113520432220122 |
7 | 40101424163235440 |
oct | 3630467156254022 |
9 | 575133601278855 |
10 | 133632433412114 |
11 | 3964121896401a |
12 | 12ba2a3b69a642 |
13 | 597463b2c13b0 |
14 | 24ddbb6a1db90 |
15 | 106b14620a10e |
hex | 7989b9b95812 |
133632433412114 has 64 divisors (see below), whose sum is σ = 250105238901504. Its totient is φ = 52137290290176.
The previous prime is 133632433412063. The next prime is 133632433412207. The reversal of 133632433412114 is 411214334236331.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 171305822 + ... + 172084134.
It is an arithmetic number, because the mean of its divisors is an integer number (3907894357836).
Almost surely, 2133632433412114 is an apocalyptic number.
133632433412114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
133632433412114 is a deficient number, since it is larger than the sum of its proper divisors (116472805489390).
133632433412114 is a wasteful number, since it uses less digits than its factorization.
133632433412114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 791331.
The product of its digits is 373248, while the sum is 41.
Adding to 133632433412114 its reverse (411214334236331), we get a palindrome (544846767648445).
The spelling of 133632433412114 in words is "one hundred thirty-three trillion, six hundred thirty-two billion, four hundred thirty-three million, four hundred twelve thousand, one hundred fourteen".
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