Base | Representation |
---|---|
bin | 1100001001111100011100… |
… | …0010110001011111010111 |
3 | 1202022200100121202020202111 |
4 | 3002133013002301133113 |
5 | 3222432441024311324 |
6 | 44231442133251451 |
7 | 2546405505060421 |
oct | 302370702613727 |
9 | 52280317666674 |
10 | 13364982650839 |
11 | 429306a311406 |
12 | 15ba281793b87 |
13 | 75c40a60a0c1 |
14 | 342c23683811 |
15 | 1829c1c24794 |
hex | c27c70b17d7 |
13364982650839 has 2 divisors, whose sum is σ = 13364982650840. Its totient is φ = 13364982650838.
The previous prime is 13364982650771. The next prime is 13364982650881. The reversal of 13364982650839 is 93805628946331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13364982650839 - 231 = 13362835167191 is a prime.
It is a super-2 number, since 2×133649826508392 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13364982650339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6682491325419 + 6682491325420.
It is an arithmetic number, because the mean of its divisors is an integer number (6682491325420).
Almost surely, 213364982650839 is an apocalyptic number.
13364982650839 is a deficient number, since it is larger than the sum of its proper divisors (1).
13364982650839 is an equidigital number, since it uses as much as digits as its factorization.
13364982650839 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201553920, while the sum is 67.
The spelling of 13364982650839 in words is "thirteen trillion, three hundred sixty-four billion, nine hundred eighty-two million, six hundred fifty thousand, eight hundred thirty-nine".
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