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133674210552941 is a prime number
BaseRepresentation
bin11110011001001101110011…
…110101011110110001101101
3122112022010111120101022100222
4132121031303311132301231
5120010104240400143231
61152145030133301125
740104433360126022
oct3631156365366155
9575263446338328
10133674210552941
1139657a06a83293
1212baab5a7947a5
1359785685bc076
142501c1b233549
15106c28dc3227b
hex799373d5ec6d

133674210552941 has 2 divisors, whose sum is σ = 133674210552942. Its totient is φ = 133674210552940.

The previous prime is 133674210552931. The next prime is 133674210552983. The reversal of 133674210552941 is 149255012476331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126611532248041 + 7062678304900 = 11252179^2 + 2657570^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133674210552941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133674210552931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66837105276470 + 66837105276471.

It is an arithmetic number, because the mean of its divisors is an integer number (66837105276471).

Almost surely, 2133674210552941 is an apocalyptic number.

It is an amenable number.

133674210552941 is a deficient number, since it is larger than the sum of its proper divisors (1).

133674210552941 is an equidigital number, since it uses as much as digits as its factorization.

133674210552941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5443200, while the sum is 53.

The spelling of 133674210552941 in words is "one hundred thirty-three trillion, six hundred seventy-four billion, two hundred ten million, five hundred fifty-two thousand, nine hundred forty-one".