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13369743349 is a prime number
BaseRepresentation
bin11000111001110011…
…00001011111110101
31021111202112022222121
430130321201133311
5204340123241344
610050355555541
7652212641404
oct143471413765
937452468877
1013369743349
115740965076
1227115bbbb1
131350b7b551
1490b8d563b
15533b3a684
hex31ce617f5

13369743349 has 2 divisors, whose sum is σ = 13369743350. Its totient is φ = 13369743348.

The previous prime is 13369743227. The next prime is 13369743371. The reversal of 13369743349 is 94334796331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13236502500 + 133240849 = 115050^2 + 11543^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13369743349 is a prime.

It is a super-4 number, since 4×133697433494 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a junction number, because it is equal to n+sod(n) for n = 13369743296 and 13369743305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13369743749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6684871674 + 6684871675.

It is an arithmetic number, because the mean of its divisors is an integer number (6684871675).

Almost surely, 213369743349 is an apocalyptic number.

It is an amenable number.

13369743349 is a deficient number, since it is larger than the sum of its proper divisors (1).

13369743349 is an equidigital number, since it uses as much as digits as its factorization.

13369743349 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4408992, while the sum is 52.

The spelling of 13369743349 in words is "thirteen billion, three hundred sixty-nine million, seven hundred forty-three thousand, three hundred forty-nine".