Search a number
-
+
13376701104811 = 111216063736801
BaseRepresentation
bin1100001010101000000110…
…0001001000001010101011
31202100210121022002101120021
43002222001201020022223
53223130440440323221
644241101024341311
72550302060224312
oct302520141101253
952323538071507
1013376701104811
114298033053310
1216005b2174837
13760557335635
14343615b33279
15182e5a8ce041
hexc2a818482ab

13376701104811 has 4 divisors (see below), whose sum is σ = 14592764841624. Its totient is φ = 12160637368000.

The previous prime is 13376701104803. The next prime is 13376701104847. The reversal of 13376701104811 is 11840110767331.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13376701104811 - 23 = 13376701104803 is a prime.

It is a super-2 number, since 2×133767011048112 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13376701102811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 608031868390 + ... + 608031868411.

It is an arithmetic number, because the mean of its divisors is an integer number (3648191210406).

Almost surely, 213376701104811 is an apocalyptic number.

13376701104811 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13376701104811 is a deficient number, since it is larger than the sum of its proper divisors (1216063736813).

13376701104811 is a wasteful number, since it uses less digits than its factorization.

13376701104811 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1216063736812.

The product of its (nonzero) digits is 84672, while the sum is 43.

The spelling of 13376701104811 in words is "thirteen trillion, three hundred seventy-six billion, seven hundred one million, one hundred four thousand, eight hundred eleven".

Divisors: 1 11 1216063736801 13376701104811